Take as input N, the size of an array. Take N more inputs and store that in an array. Take another number’s input as M. Write a function which returns the index on which M is found in an array, in case M is not found -1 is returned. Print the value returned.
It reads a number N.
2.Take Another N numbers as an input and store them in an Array.
Take another number M as an input.
If M is found in the Array the index of M is returned else -1 is returned and print the value returned.
Input Format
Constraints
N cannot be Negative. Range of Numbers can be between -1000000000 to 1000000000. M can be between -1000000000 to 1000000000.
Output Format
Sample Input
5
2
4
6
9
17
17
Sample Output
4
Explanation
Given array = {2, 4, 6, 9, 17}. Target number = 17. Index = 4.
#include
#include
using namespace std;
int main() {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
int m = INT_MIN;
cin >> m;
for (int i = 0; i < n; i++) {
if (arr[i] == m) {
return i;
}
}
// Return 0 even if the m is not found in the array.
return 0;
}
error is coming please help me with this