Leetcode doubt o sme lines

#1

class Solution {
public:
string removeOuterParentheses(string s) {
int n = s.size();
if(n<2)
return “”;
string out;
stack st;
int balance =0;
int starting =0;
for(int i =0;i<n;i++){

    if(s[i]=='(')
        st.push(s[i]);
    else{
        if(st.size()>1)
            st.pop();
        else
        {
            if(!st.empty()){
                st.pop();
            balance = i;
            out += s.substr(starting+1,balance-starting-1);
           // cout<<balance<<" "<<starting<<endl;
            starting = i+1;
            //cout<<balance<<" "<<starting<<endl;
            }
        }
        
        
            
    }
}

return out;

}
};

In this code I cannot understand the

//balance = i;
out += s.substr(starting+1,balance-starting-1);
// cout<<balance<<" “<<starting<<endl;
starting = i+1;
//cout<<balance<<” "<<starting<<endl;
//

Please help me here

#2

hello @Somasree

in which line u have doubt?

#3

balance = i;
out += s.substr(starting+1,balance-starting-1);
// cout<<balance<<" “<<starting<<endl;
starting = i+1;

In these lines

#4

in starting variable they are storing starting index of the pattern (Ie from where the new pattern starts)

balance is variable that holds ending index of pattern (ie where the pattern ends)

in this line they are adding [staring+1…balance-1] part of given string to their answer (ie out string) . { starting +1 becuase we have ( at index starting we want to remove it , similarly balance-1 becuase we have ) at index balance and we want to remove it).

and becuase pattern ends here , new pattern will start from index i+1

thats why we have this line.

#5

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