Issue with string tokenizer

#1

char *myStrtok(char *input,char delim){

static char * ptr;
if(input!=NULL){
	ptr = input;
}
if(ptr==NULL){
	return NULL;
}


char* output = new char[strlen(ptr)+1];

int i;
for(i=0;ptr[i]!='\0';i++){
	if(ptr[i]==delim){
		output[i] = '\0';
		ptr = ptr + i + 1;
		return output;
	}
	output[i] = ptr[i];
}

output[i] = '\0';
ptr = NULL;
return output;

}
in this would the for loop not return each output but in strtok function we need only 1 output at a time

#2

why have we used pointer her why not static char input = NULL;

#3

why have we used pointer her why not static char *input = NULL;

#4

HI @abhay170, no it will not because we have written here that
as soon as ptr[i] will be equal to delimiter then the output string will be returned. Once return statement is read and executed, the flow of control of program will go back to the parent function, and rest of loop will not be executed.

Hope this helps :slight_smile:

#5

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