Increasing order using recursion

#1

if only cout<<n is mentioned, and the value of n is constant then how are all numbers printing in the increasing order?

#2

@ebanigupta121 I think you did not get the concept well of recursion. The increasing or the decreasing order of printing depends on the position of cout statement relative to the recursive call. If cout statement is before the recursive call, then it is printing in decreasing order. If you place the cout statement after the recursive call, then it prints in increasing order. Refer the video again if you did not get it.

#3

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