In the question sort game?

#1

in the question sort game? why operator overloading is being used. Cant we do it without it, by simply writing a<b;

#2

hi @mehulbhandari358 where is operator overloading used? Please share the code if you are talking about some particular approach

#3

it is used in the editors code

#4

@mehulbhandari358 please share the code you’re talking about.

#5 
#include <iostream>
#include <vector>
#include <string>
#include <algorithm>

using namespace std;


class Employee
{
    public:

    int salary;
    string name;

    Employee( int sal , string nam)
    {
        salary = sal;
        name = nam;
    }
};

bool operator>( string s1 , string s2 )
{
    int min = s1.size() < s2.size() ? s1.size() : s2.size(); 

    int index = 0;

    while( index < min && s1[index] == s2[index])
    {
        index++;
    }

    if( index >= min )
    {
        if( s1.size() > s2.size() ) return true;
        else return false;
    }

    if( s1[index] > s2[index] ) return true;
    else return false;

}

bool lol( Employee e1 , Employee e2 )
{
    if( e1.salary > e2.salary )
    {
        return true;
    }
    else
    if( e1.salary < e2.salary )
    {
        return false;
    }

    return e2.name > e1.name;
}

void sort2( vector<Employee> &v )
{
    sort( v.begin() , v.end() , lol);
}

int main()
{
    int n2;
    cin >> n2;

    int n;
    cin >> n;

    vector<Employee> v;

    for(int i = 0 ; i < n ; i++ )
    {
        string s;
        cin >> s;

        int n;
        cin >> n;

        Employee E( n , s);
        v.push_back(E);
    }

    sort2(v);

    for(int i = 0 ; i < n ; i++ )
    {
        if( v[i].salary < n2 ) break;

        cout << v[i].name << " " << v[i].salary << "\n";
    }

    return 0;
}
#6

@mehulbhandari358 here they used a class to define employee but you can use a simple pair datatype also. make a pair of pair<int, string> type and use STL sort function on it

#7

can we use sort on class employeee

#8

Look at the sort2 and lol function, that’s what is being done here

#9

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#10

yeah i have seen it but in “lol” function that part of code is not needed as “>” this can we used directly because of operator overloading

#11

@mehulbhandari358 there are different methods of doing things, is there a doubt here?

#12

i am asking can i use it directly . due to operator overloading ?

#13

@mehulbhandari358 directly how? Share a code snippet

#14

The operator overloading is done here to compare the strings. Otherwise they would be compared according to lexicographical order

#15

that’s what we want , to compare acc. to lexicographical order