IM getting an error . please tell me the correct apporach or my error

#1
#2

@Anchal
Don’t check if(root1->data!=root2->data) as we are only concerned about the structure and not the data. While the data may be different , the two trees are required to have the same structure.

Your code gives a runtime error when the compare function reaches a condition when both root1 and root2 are NULL. You have not employed a check for this condition and your code tries to access the right and left part of NULL trees thus giving you a runtime error. Please correct it.

#3

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