I had tried to excute the logic but program is trapped in the sort function and "bye you" is never printed

#1

#include
#include
#include
using namespace std;

string extract_key(string s,int k)
{
char *ch=strtok((char *)s.c_str()," “);
while(k>1)
{
ch=strtok(NULL,” ");
k–;
}
return (string)ch;
}

int to_int(string s)
{
int p=1;
int ans=0;
for(int i=s.length()-1;i>=0;i++)
{
ans+=((s[i]-‘0’)p);
p=10;
}
return ans;
}
bool compare(pair<string,string> s1,pair<string,string>s2)
{
string key1,key2;
key1=s1.second;
key2=s2.second;
cout<<key1<<" “<<key2<” ";
return to_int(key1) < to_int(key2);
}

int main()
{
int n;cin>>n;
cin.ignore();

string str[n];
for(int i=0;i<n;i++)
getline(cin,str[i]);

int key;
string reverse,ordering;
cin>>key>>reverse>>ordering;
cout<<ordering<<endl;

pair <string,string> strpair[n];
for(int i=0;i<n;i++)
{
	strpair[i].first=str[i];
	strpair[i].second=extract_key(str[i],key);
	cout<<strpair[i].second<<" ";
}

if(ordering =="numeric")
 sort(strpair,strpair+n-1,compare);

else
sort(strpair,strpair+n);
cout<<"bye";
for(int i=0;i<n;i++)
cout<<strpair[i].first<<endl;

}

#2

I`ll debug the question and let u know the problem

#3

@Nidhi_Alipuria
bro

int to_int(string s)
{
int p=1;
int ans=0;

for(int i=s.length()-1;i>=0;i–)

in the to_int function u have incremented the value of i it should be – since u are starting from s.length()

and also u havent understood the question completely the sort function has variety of varaition
sorting is also based on key 1
u need to find out the part 1 of the string not just the second part

please try it out furthur in case u are unable to do it comment below i`ll help

#4

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