I do not understand a syntax

#1

wdym by
ll denom=1ll
here ll is long long, just saying

#2

@sshreya2912
Yes, ll is long long.
1LL means 1 whose datatype is long long .
It is a good practice to initialise long long variables to long long values. It may not be evident why in this case. but try to run this code.
long long a = 1LL;
cout << max(a, 2);
it will show error because in max() a is long long and 2 is int.
to make this work, we do max(a,2LL).

#3

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