I couldn't think anything about how to achieve it

#1

I figured out how to check if 3 entered number is a pythagorean triplet.

But I couldn’t think of any logic about how to frame the algorithm for this q. Please help me with this quetsion.

#2

Hello @sinchan1509_1a917d7b6cc3cbb9,

You can check my implementation for the same,

#5

Can you please explain this code to me as I am not able to understand it

#6

Hello @sinchan1509_1a917d7b6cc3cbb9,

  1. If n <= 2 there are no triplets.

  2. If n is even, then,
    a = (N*N)/4 -1
    b = N
    c = (N*N)/4 +1
    You can verify that a*a + b*b = c*c

  3. If N is odd, then,
    a = ((N*N) + 1)/2 - 1
    b = N
    c = ((N*N) + 1)/2
    You can verify that a*a + b*b = c*c

You can also refer from here,

#7

ok thank you so much for help

#8

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