Https://ide.codingblocks.com/s/479552

#1

I am not able to understand where i am wrong in this question its not printing the answer

#2

hello @architsuryavanshi

x will be zero in the last loop. thats why it is not printing anything.
u need to find the number of digit in the x and store it as size and then apply any logic.

btw string is good datastrucutr for this problem.

read a number as string (say s) .
if left most character is ‘9’

  • then leave the leftmost character as it is and for other characters simpl replace s[i] with min(s[i],‘9’-s[i])

else:

  • for each i replace s[i] with min(s[i],‘9’-s[i])

print s

#include<bits/stdc++.h>

using namespace std;

int main() {

    string n;

    cin>>n;

    int start=0;

    if(n[0]=='9')

       start=1;

    for(int i=start;i<n.length();i++){

            char c='9'-n[i]+'0';

            n[i]=min(n[i],c );

    }

    cout<<n;

    return 0;

}
#3

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