How to take Input

#1

Can you please provide the code how to take input

#2

1 2
1 has 2 children now move to its childrens
2 2
2 has two children (als 2 is children of 1)
3 0
3 is one of the children of 2 and it has zero children means leaf node
4 0
4 is 2nd children of 2 and it has zero children means leaf node
5 2
5 is 2nd children of 1 and it has two children 6 and 7 see next two lines
6 0
7 0
2 (this is the level no)

use recursion to take input

hint:

Node* InputForGenricTree(){
        //Enter Node Data 
        int d; cin>>d;
        Node* nn=new Node(d);
        // Enter no of children for node#
        int c; cin>>c;
        nn->child_count=c;
        nn->children=new Node*[c];
        for (int i=0;i<c;i++){
            nn->children[i]=InputForGenricTree();
        }
        return nn;
    }

if you have more doubts regarding this feel free to ask
and if your doubt is resolved please mark it as resolved from your doubt section in your course

#3

little bit confusing can you please explain use -> opertor instead of & operator

#4

-> is use to acess member of pointer (of object)

& this is for address of variabel

#5

please write code in coding blocks ide and share link for same(takin input only)

#6
#7

giving correct output but passing testcase

#8

passing or not passing testcases??

my code is just to take input
rest of code you have to write