How to pass it for negative numbers

#1

#include
#include
using namespace std;
int main() {
long long int n;
cin>>n;
if(n<0)
{
n*=-1;
}

long long int help;
help=n;
long long int digit=0;
while(help!=0)
{
    help=help/10;
    
    digit++;
}

int counter=0;
int answer=0;
int remainder=0;

while(counter!=digit-1)
{
      remainder=n%10;
      if(remainder>=5)
      {
          remainder=9-remainder;

      }
      answer+=(remainder)*(pow(10,counter));
      n=n/10;
      counter++;
      
}
if(n!=9&&n>=5)
{
    n=9-n;
}
answer+=(n)*pow(10,counter);
cout<<answer;

}

#2

@Bhavit_Singla
hello bhavit,
pls check the constraint u will never be given any negative number.
image

#3

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