How the output of this code is getting printed in next line.please explain me the code

#1

we are doing ans.pushback() then how it is getting printed in next line

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#2

@Prabhleen_sheenu ans is a 2D vector, you are not printing anything, just for sake of visible convenience, they are shown in different line!

#3

yes its a 2d vector but how it gets to know that what is in second row?

#4

you can simply iterate this way
for(int i=0;i<ans.size();i++)
{
for(int j=0;j<ans[i].size();j++)
cout<<ans[i][j]<<" ";
cout<<endl;
}

#5

yea sir… my doubt is without writing these lines(2 for loops) usme kaise horha yeh
for(auto it=m.begin();it!=m.end();it++)
{
ans.push_back(it->second);
}

or jaise apne cout k liye 2 for loops se kiya hai pushback kaise kr skte hain 2 for loops se

#6

@Prabhleen_sheenu

here it->second is a vector of string, so you are pushing vector in a vector of vectors, which is valid
Also this can also be done using 2 for loops!(but do it directly)

#7

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