How cin>>d; can call the overloaded operator >> as it is like a function so we need to pass arguments . we pass arguments like func_name(argument 1, argument 2 ,...) but how the arguments are being passed when we overloaded >> and <<?

#1

how cin>>d; can call the overloaded operator >> as it is like a function so we need to pass arguments . we pass arguments like func_name(argument 1, argument 2 ,…) but how the arguments are being passed when we overloaded >> and << ? I cant see how the arguments are passed and recieved by overloaded functions. kindly explain in detail pls

#2

I cant see how the arguments are passed and recieved by overloaded functions. kindly explain in detail pls

#3

Hello @Rahulkr102

Like we use functions and send arguments to them like foo(arg1, arg2)
binary operators when overloaded send the left operand and the right operand as arguments.
like c1 = c2 + c3 where + is overloaded for c type objects, c2 and c3 are send as arguments.

These are different styles or syntax to achieve what we want in a readable format.
So in cin >> d it will send cin and d as left and right operands respectively.

#4

But when + operator is overloaded we sent /passedonly one argument. Kindly refer the video .
You told binary operator send two arguments viz left and right.
Kindly explain in detailu

#5

@Rahulkr102

Yes the video’s correct.
One object (the left one) is the one whose method is being is called and the right one is passed as argument

Example
class C {
int data;
C operator+(const C& x) {// stuff}
}
int main() {
C c1, c2, c3;
c1 = c2 + c3
}

The above line c1 = c2 + c3 is equivalent to
c1.operator(c3)

Let me know if you still need any help.

#6

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