How aan i solve this?

#1

How can i solve this please help me

#2

Hey @chemant077
The product of all the divisors of a number N is N^x where x is the number of divisors of N. The number of divisors is given by product of prime powers+1 for N. for example if N = 12 than its number of divisors are (2+1)*(1+1) = 6. you are already given the prime powers of N hence its number of divisors can be calculated.

#3

we need to find no of diviors of N^x ??

#4
#5

its just showing compilation error

#6

am waiting here for the response maam

#7

@chemant077
Your code is getting compiled successfully.

#8

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