Here why have we put 1 for the constant in the end of the new second transformation matrix?

#1

Ideally if we are writing everything in reverse order then the coefficient of that should also come in the end.

#2

Hi @sakshi_singhal,

We can’t put the coefficient at the end.
because if put the coefficient at end then,
L.H.S = 4*f(i-4) + 0*f(i-3) + 2*f(i-2) + 1*f(i-1) + 1*d
R.H.S = d

L.H.S != R.H.S

#3

How RHS would be d? LHS is ok.

#4

Hi @sakshi_singhal,

This is your matrix A,
image

matrix B,
image

If you observe, last row of matrix B has d.
that’s why R.H.S = d

#5

Still unable to get you

#6

@sakshi_singhal,

You can put coefficients at the end if in the resultant matrix f(i) and d are placed like this.
image

#7

yes so what is wrong in this?

#8

@sakshi_singhal,

nothing is wrong it is just design you can use it in both ways.

#9

ok, got it, thanks for it

#10

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