Help with error

#1

prob: https://hack.codingblocks.com/app/contests/2022/1100/problem

sol: https://ide.codingblocks.com/s/408029

I’m getting a seg fault on hackerblocks and on sublime it is not functioning properly , for now I just want to fix that.

#2


Check now .

#3

thanks, at this point I have separated the 2 linked lists, temp is the tail of the linked list which is to be appended at the start of the original one, so when I do temp-> next = head why is it not working.

#4

Send me your updated code. Will look into it.

#5
#6

oh I realize why is not working because I don’t have access to the head of the new linked list form, right?

#7

what you are doing is this

k = 3
        1 2 2 1 8 5 6
              ^     ^
              |     |
            temp1   temp
   head
       1 2 2 1 NULL
       6->1

You are doing this
Instead do this

k = 3
1 2 2 1 8 5 6
^     ^ ^   ^
|     | |  (A)
head  | temp 1   
     temp 
First break the linked list temp ->next = NULL {1,2,2,1}
(A) ->next should point to head 
return temp 1 as final linked list will be {8,5,6,1,2,2,1}

Also keep this in mind that k can be greater then n , so before passing the argument do k = k % n

#8

I did the changes but getting seg fault, I don’t understand how k can be greater than n

#9

Check this

That’s a side case which is handled in the code i am attaching in this message [line number 47]

#10

I implemented the logic from your code into my code but I’m getting a seg fault

#11

Line number 18 was causing segmentation fault, the logic i told you is still not correctly implemented by you. You are close. Just dry run your code and you will know where were you wrong.

#12

1 tc is failing

#13

Check now =>

#14

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