Getting wrong answer

#1


getting wrong answer

#2

hi @sp5513
Read the problem as a matrix of size M x N, rather than N x M as it helps in easy visualization.
In this manner,

  • A tile can be either place vertically,meaning it will only occupy a cell of width 1 and a complete hieght of M. Or,
  • You can place M tiles horizontally one over the other if there is enough width left.

refer this code -->

#3

hi @sp5513
i hope its clear now??

#4

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