i tried a lot on this error but am not able to solve the problem here is the code
import java.util.*;
public class Main {
public static void main(String args[]) {
Scanner in=new Scanner(System.in);
String p=in.next();
char q;
int r;
for(int i=0;i<p.length();i++)
{
q=p.charAt(i);
r=(int)q;
if(9-r<r)
{
p=p.substring(0,i)+r+p.substring(i+1);
}
}
System.out.println(p);
}
}
see the ascii value of an integer is not the same integer…you are assuming that if you will typecast character 0 to integer you will get 0…but actually the ascii value of 0 is somewhere around 47…if you want to get the integer value then write r=q-‘0’;…
for ex)if q=‘3’(ascii value-50)
then r=q(50)-‘0’(47);
so r will have value 3…
one more thing if 9-r is less than r then (9-r) should come in place of ith character(refer to the place where you are taking susbstring)
also you need to take care of some edge cases in your code…
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