General doubt........please help

#1
#2

hello @hg11110000

image

u have written code for the same.
this function will fill all rechable positions with 1 (from x,y).

maintain one visited array to avoid visiting same state again (rest is correct).

#3

@aman212yadav

run the code…

its giving all garbage output’

0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 139856813689472 18
94341132529008 139856813440973 196100078 439 264 16216 0 1328
728 1864 312 24 533 24 4096 5669
0 0 0 139856813223380 0 0 7 139856813079312
64 139856813079248 139856813681280 0 288230380446694912 139856813223583 0 64
141733920768 33 0 94341132518261 1 140722327577528 140722327577544 0

0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 139856813689472 18
94341132529008 139856813440973 196100078 439 264 16216 0 1328
728 1864 312 24 533 24 4096 5669
0 0 0 139856813223380 0 0 7 139856813079312
64 139856813079248 139856813681280 0 288230380446694912 139856813223583 0 64
141733920768 33 0 94341132518261 1 140722327577528 140722327577544 0

#4

… . . . … . . . . . . . .

#5

@aman212yadav

still not correct :frowning:

where i m going wrong ?

#6

@hg11110000
i have updated ur code pls check.


a)
read input as char

#7

@aman212yadav

how it able to go ahead in 2nd test case although P is there as a barrier ??

it should visit only the top right triangle only naa ??

#8

@hg11110000
i have answered ur general doubt.
u were asking from x,y u need to mark all rechable state to 1.

#9

how to add this above said thing ?

@aman212yadav

#10

simply add b[x][y]==‘P’ in ur if statement of f function.

#11

yeah thanks…understood now the flow !!

@aman212yadav

#12

@aman212yadav

cant i just check if at the diagonal of king if the bishop visited…then the ans is yes ???

its not passing test cases now also ???

#13

@hg11110000
check now->

u only have to check position of king ,if it is visited then yes otherwise no