FIbbonacci pattern

#1

#include

using namespace std;

int main()
{
int n,a=0,b=1,sum;
cin>>n;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
cout<<" ";
}
while(sum<=n)
{
cout<<“a”;
sum=a+b;
a=b;
b=sum;

}

}
return 0;
}

#3

Hey , you print 0 before for loop then start your for loop from i=2 keep printing your elements inside nested loop and just add them after printing to generate next number of sequence

#4

hey, @shdanish1508 simply you take a temp variable and do it please refer to this if you still have doubt(https://ide.codingblocks.com/s/172760) or if you had solved it please mark this doubt as resolved

#5

i am not understanding the code cud you expalin the code again

#6

our fibbonaci pattern is 0,1,1,2,3,5…
1.keep 0 in sum and 1 in adder initially.
2.print sum(=0).
3. now your adder for next element will become this sum (since to generate next element we have to add previous sum the current sum) so store in it a temp and change your sum to next element of pattern sum=sum+adder=1.
4.update temp to the adder(=0)
process will be repeated till your for loop runs.hope it helps.
if still have doubt please ask else please mark this doubt as resolved.thankyou.

#7

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