Fast Fibonacci(Two test case fail)

package competitive;

import java.math.BigInteger;
import java.util.Scanner;

public class FastFIBONACCI {
static int mod = 10000007;

public static void main(String[] args) {
	// TODO Auto-generated method stub
	Scanner sc = new Scanner(System.in);

	int t = sc.nextInt();
	while (t-- > 0) {
		long n = sc.nextLong();
		System.out.println(fab(n));
	}

}

public static BigInteger fab(long n) {
	long t[][] = new long[2][2];

	for (int i = 0; i < 2; i++) {
		for (int j = 0; j < 2; j++) {
			if (i < 1) {
				if (j == i + 1) {
					t[i][j] = 1;
				} else {
					continue;
				}

			}
			t[i][j] = 1;
		}
	}
	t = power(t, n - 1);
	long f1[] = { 1, 1 };

	BigInteger ans = new BigInteger("0");
			for(int i = 0; i < 2; i++) {
				//long k = (t[0][i] * f1[i]) % mod;

		ans = ans.add(BigInteger.valueOf((t[0][i] * f1[i]) % mod));
	}
	return ans;
}

public static long[][] power(long arr[][], long b) {
	if (b == 1 || b == 0) {
		return arr;
	}
	if ((b & 1) != 0) {
		return mutiply(arr, power(arr, b - 1));
	} else {
		long s[][] = power(arr, b / 2);
		return mutiply(s, s);
	}

}

public static long[][] mutiply(long[][] t, long[][] power) {
	// TODO Auto-generated method stub
	long ans[][] = new long[t.length][t.length];
	for (int i = 0; i < t.length; i++) {
		for (int j = 0; j < t.length; j++) {
			for (int x = 0; x < t.length; x++) {
				ans[i][j] = ((ans[i][j] + ((t[i][x] * power[x][j]) % mod)) % mod);
			}
		}
	}
	return ans;
}

}

please help me. to solve this problem

You can read here for the idea.
https://codeforces.com/blog/entry/14516

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