Doubt related to string pointers

#1

If I write
char* s = “something”;
s[0] = ‘t’;
It will give error !!

char s[] = “something”;
s[0] = ‘t’;
this works why??

#2

One more thing to mention that
in the case of:
char* s = “smthg”;
i can access the data like this:
cout << s[0] << endl;

But I cannot change the data:
s[0] = ‘t’; // gives error

And if i print the addresses, both are different…
cout << (void*)x << endl;
cout << (void*)x[0] << endl;

#3

this is bcz most of the times string literals are stored in read only memory, so it shows error when you try to update

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