public class stackisbuilding {
public static void main(String[] args) {
// TODO Auto-generated method stub
printdecreasing(5);
}
public static void printdecreasing(int n)
{ if(n==0)
{
return ;
}
System.out.println(n);
printdecreasing(n-1);
System.out.println("*");
}
}
in this program when base case is achieved then where the return statement will go? and why it is printing five times (*) in the output?
After the base case return statement, the flow will go back to the function with the value it called itself when the base case hit. Meaning, when n=1 called printdecreasing(0), base case got it and the function return itself back to when n was = 1.
‘*’ is printing 5 times because the function ran 5 times when n was = {1,2,3,4,5}. Everytime the function finishes its code, the flow of control goes back to the function and its value which called it. Thats why * was printed 5 times. First when n=1, then n=2, then n=3 , n=4 and last when n=5
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