Doubt in my approach

#1


i am trying to find if the root of a tree becomes null and thr root of other three does not so the are not identical

#2

yes you can try this approach

the code you have share does not contain any function related to “structurally identical”

Reference Code

bool isStructurallyIdentical(node*root1,node*root2){
	if(root1==NULL&&root2==NULL){
		return true;
	}
	if(root2==NULL||root1==NULL){
		return false;
	}

	bool lans=isStructurallyIdentical(root1->left,root2->left);
	if(lans==false)return false;
	bool rans=isStructurallyIdentical(root1->right,root2->right);
	return rans;
}
#3

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