Double side arrow

#1


sir my approach is too messy even I have passed all the test case I am not able to understand it can u suggest me another way to do this question

#2

hi @anuragavm123

there is no problem with your approach it’s good

program is not that messy

#3

but sir still I am not able to understand question

#4

@anuragavm123

you have use this approach
read this
Approach:

  1. In the given example, N=7 and the number of ROWS is 7.
  2. VERTICALLY, the pattern GROWS till ROW=N/2 and SHRINKS afterwards.
  3. ROW 1 has 4 ” “(SPACE) characters and then a value.
  4. The number of SPACE characters decreases whereas NUMERALS increase in count in each successive row.
  5. Also, note that the 1st value of the number placed in each row is the same as the number of the row.
  6. Also HORIZONTALLY the pattern has NUMERALS, then SPACES and NUMERALS afterwards.

from this which thing you don’t understand?
i will explain you

1 Like
#5

yes sir I understood this much I am not able to understand how to create space in between the pattern like 2 row has 1 space , 3 row has 5 then 7. can u expain that

#6 
              1
           2 1 1 2
        3 2 1   1 2 3
     4 3 2 1     1 2 3 4
        3 2 1   1 2 3
           2 1 1 2
              1

see the pattern
there are 2i+1 spaces in b/w nos where i is row no
for i=0 spaces=1
i=1 space=3
i=2 spaces=5 and so on…

so you can write like

for(int j=0;j<2*i+1;j++){
   cout<<"  ";
}
#7

sir for I=0 we are taking second row and I=1 we are taking 3 row??

#8

okay then use
2*i-1 this will also work

for(int j=0;j<2*i+1;j++){
   cout<<"  ";
}