Does not got how you find max range?

#1

Ceil(log2(n))
if n=9

then ceil is 3.16 how you say 15 ??

#2

ceil(3.16) would be 4 as decimal is rounded off to the next integer

#3

Ok 4 but how max range of n comming is 15 ?

#4

can u share snippet of what u are exactly referring to??

#5

https://online.codingblocks.com/app/player/206137/content/192993/6881/lecture

At 3:00 how he has calculate range of 9 by using ceil(logN)
how max range is 15 ?

#6

so after doing ceil what we are doing is taking 2^4 - 1 = 15

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#7

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