we have break (a-b)%N=a%N -b%N
then how we will break (a/b)%n?
Division modulo
Hi @anshuman, for computing (a/b)%n we have to use the concept of multiplicative inverse and to compute multiplicative inverse we need to know extended euclidean algorithm . so if you are not well versed with the concept of multiplicative inverse then i highly suggest you to know it first
you can refer to these for more info :
In case of any doubt feel free to ask 
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