is there some hidden condition for this.
The sum of digits if odd and divisible by 3, the output should be yes and if the sum is even and divisible by 4, the output should be yes. else no.
But it doesn’t pass the test case.
Delhi's odd even
@Himanshu-Sajwan-2271264282963988 You have to find the sum of all digits which are even and the sum of all digits which are odd separately. If the sum of all even digits is divisible by 4 or sum of all odd digits is divisible by 3, then only print “Yes”. In all other cases print “No”.
i have done same thing but output is wrong answer.