Delhi odd even program

#1

#include
using namespace std;
int main()
{ int n,no;
cin>>n;
int i=1;
while(i<=n)
{
cin>>no;
int sum=0;
while(no>0)
{
int r=no%10;
sum=sum+r;
no=no/10;
}
if(sum%2==0 && sum%4==0)
cout<<“Yes”<<endl;
else if(sum%2!=0 && sum%3==0)
cout<<“Yes”<<endl;
else
cout<<“No”<<endl;
i=i+1;
}
}

#2

Check now=>


Question wasn’t clear to you, you have to take each digit as a number and then have to add, dry run this code by me. You will get the error.

#3

it still not working if i enter number 12589 it is printing yes as its sum is odd and it is not divisible by 3 but still it is printing “yes”

#4

See when you enter 12589 your es is 10 & os is 15 in which 15 is divisible by 3 but es is not divisible by 4, so since out of these 2 conditions one is correct. We will print yes.
Cause
os is 9 by adding 9
es is 8 by adding 8
os is 14 by adding 5
es is 10 by adding 2
os is 15 by adding 1

#5

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