Constructor and parameterized constructor

#1

char name[20]
char *n
strcpy(name, n)

this is basically happening where i have a doubt
Why did we define char *n as a pointer variable?

#2

we did so in order to create a string literal.
char *n will create a pointer and it will be assigned the address of string literal.

#3

but it is working even if we just copy the value normally without using pointer.
what is the problem in that?

#4

That’s because char* s=“pointer”;
is similar to
char name[] = “pointer”;
char *s = name;

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