Concept of 4:16

#1

it should be if(a[current]==a[previous])
if it is not equal than there is no duplicacy, if current is copied in previous without duplicacy then it will change the code

Eg: Input string - Codding

please explain

#2

the code is correct, it should be a[current]!=a[prev];
for eg. say input is ccooooddinng, your output should be “coding”.
prev always points to the last index of so far formed solution.
the condition will be first time true when current = 2 and prev = 0, it means we got next character(which is ‘o’) after skipping all duplicates of c. so partial solution till now should be ‘co’, and thats why prev++, and a[prev] = a[current];
this means array will be coooooddinng at this time and prev =1 , the partial solution is ‘co’ from index 0 to prev.

thanks

#3

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