Code for this qstn

#1

#include
#include<bits/stdc++.h>

#include
using namespace std;

bool cmp(int a,int b)
{
if(a>b)
return a>b;
else
return b>a;
}

/bool compar(int a,int b)
{
int s,r;
int A=a,B=b;
while(a%10==a)
{
a=a/10;
}
s=a;
while(b%10==b)
{
b=b/10;
}
r=b;
if(s<r)
return b>a;
else
return a>b;
if(s==r)
{
return cmp(A,B);
}
}/

bool compar(int a,int b)
{
int c1=0,c2=0;
while(a>0)
{
c1++;
a/=10;
}
while(b>0)
{
c2++;
b/=10;
}
c1–;
c2–;
int a1=a/(pow(10,c1));
int b1=b/(pow(10,c2));
if(a1>b1)
{
return a>b;
}
else
return b>a;
if(a1==b1)
{
return cmp(a,b);
}
}

void funct(int a[],int n)
{
sort(a,a+n,compar);
for(int i=n-1;i>=0;i–)
{

	cout<<a[i];
}

}

int main() {

int t,n,a[100];
cin>>t;
while(t--)
{
	cin>>n;
	for(int i=0;i<n;i++)
	{
		cin>>a[i];
	}
	funct(a,n);
}
return 0;

}

#2

you’ve made this code too complex all you need to do is take input as string and compare on the basis of if s1 + s2 > s2 + s1.
Code

#3

how to understand that input should be taken as string when constraints are given for int

#4

since the question mentions that concatenation is involved and since it is easier to concatenate string then integers it is a good idea to use strings instead of integers.

#5

yea its complex but if we want to take the input in the form of integer then how to solve it?

#6