Chewbacca Number Problem

#1

What could I have missed?
#include
using namespace std;
int main() {

int x,count,z;
count = 1;
cin>>x;
int y=x;
while ((x/10)!=0){
	count++;
	x = x/10;
}
z = 0;
int arr[count];

for (int i=0; i<count; i++){
	arr[count-i-1] = y%10;
	y = y/10;
}

for (int j=0; j<count; j++){
	while (arr[j]==9){
		arr[j] = 9-arr[j];
	}
	if (arr[j]>=5){
		arr[j] = 9-arr[j];
	}
	
}
int f = 1;
for (int i=0; i<count; i++){
	z = z+(arr[count-i-1]*f);
	f = f*10;
}

cout<<z;
return 0;

}

#2

@Chirag-Jain-1414278322030453
hello chirag if first digit is 9 then u cannot change it to 0.
for example
if x=9888
then answer should be 9111

#3

I changed the code to:

#4

#include using namespace std; int main() { int x,count,z; count = 1; cin>>x; int y=x; while ((x/10)!=0){ count++; x = x/10; } z = 0; int arr[count]; for (int i=0; i<count; i++){ arr[count-i-1] = y%10; y = y/10; } if (count==1){ if (arr[0]==9){ arr[0] = 9; } else{ if (arr[0]>=5){ arr[0] = 9-arr[0]; } } } else{ for (int i=0; i<count; i++){ if (i==0){ if (arr[i]!=9 and arr[i]>4){ arr[i] = 9-arr[i]; } else if (arr[i]==9){ arr[i] = 9; } } else{ if (arr[i]>4){ arr[i] = 9-arr[i]; } } } } int f = 1; for (int i=0; i<count; i++){ z = z+(arr[count-i-1]f); f = f10; } cout<<z; return 0; }

#5

But there are still test cases failures

#6

Please save your code on ide.codingblocks.com and then share its link.

#7

link for code : https://ide.codingblocks.com/s/195453

#8

Check it now…Since the constraints are very large, you must use long long int

#9

it still seems to not work after changing int to long long int. Link to code - https://ide.codingblocks.com/s/195872

#10

Replace line 50 with long long int f = 1;

#11

I found another approach
code:
#include<bits/stdc++.h>
using namespace std;

int main(){

string str;
cin >> str;
for(int i = 0; i < str.length(); i++){

    int a = str[i]-48;
    if(a>4){
        a = 9 - a;
    }
    if(!a && !i)continue;
    str[i] = a +'0';
}
cout << str << endl;

return 0;

}