Chewbacca And Numbers

#1

How to handle the case when we have number like this 999, 9 etc.

#2

Hi @Vikaspal
store the number as string. run a while loop till s[i]==‘9’ and after that solve the question as stated.
Hope dis resolves ur doubt

#3

for another number its works fine

int main() {
long int num;
int rem;
long int ans=0;
int mul=1;
cin >> num;
while(num != 0) {
// addeding the remainder and ones, tens digits. each time increment
rem = num%10;
if(rem >=5 && rem != 0) {
rem = 9 - rem;
}
ans = ans + remmul;
mul = mul10;
num = num/10; // take the next element/character
//cout << num << " ";
}
cout << endl << ans;
return 0;
}

#4

In ur code, when u are acquiring 9 ur code is converting it to 0. so when u give 9991 as input, it convert 9991 to 0001 and the output comes out to be 1.
To avoid dis, u can first store 999 in ur answer and then perform all ur operations.
eg. input=99911289
so first store 999 in ans. and then perform all ur operation on d code which will give 99911210 as output.

#5

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