Can we convert jzzhu and numbers to problem vim aWar

#1

In Vim War there is a mask m . and we have to calculate all such subset whose “or” will give that msk.
Let’s come to jZZhu and numbers,
if a & b = k.
then ~(a&b) = ~k
i.e a or b = ~k.
So, in jzzhu and numbers we have mask as (1<<BIT)-1.

#2

if a&b = k then it is not compulsory that ~(a&b) = ~k.
For example a=5 (101) and b=3 (011) , then (a&b) = 001 and ~(a^b) = 110 .

#3

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