Calculate the sum: last test case error. Problem in code?

#1

#include
#include <math.h>
using namespace std;
int main() {
int long long n;
cin >> n;
int long long a[n]={0};
for(int long long i=0;i<n;i++){
cin >> a[i];
}
int long long q;
cin >> q;
int next[n]={0};
int long long sec = n-1;
while(q!=0){
int x;
cin >> x;
if(x>0){
int long long j=x;
while(j!=0){
for(int long long i=0; i<n; i++){
next[i]=a[i]+a[sec];
//cout << next[i] << " ";
sec = i;
}
for(int long long i=0;i<n;i++){
a[i]=next[i];
}
j–;
}
}
//cout << endl;
if(x==0){
for(int long long i=0;i<n;i++){
next[i]=a[i]+a[i];
//cout << next[i] << " ";
}
}
for(int long long i=0;i<n;i++){
a[i]=next[i];
}
q–;
}
int long long sum = 0;
for(int long long i=0;i<n;i++){
sum+=a[i];
}
//cout << sum;
int long long ans;
int long long base = pow(10,9)+7;
ans = sum % base ;
cout << ans;
return 0;
}

#2

kindly share the link of code
so that i can run and check what’s wrong

#3
#4

i think you have misinterpreted the question
if array is of size 5 and this is the array {1 2 3 4 5 } and x=2 then new array will be
{1+4,2+5,3+1,4+2,5+3}

you can refer this simple code

#5

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