1
232
34543
4567654
567898765
Basics of Problem SolvingPseudocode AssignmentPseudocodesWrite pseudocode to print the following pattern
int n; cin >> n;
for (int i = 0; i < n; i++) {
for (int j = i + 1; j <= 2 * i + 1; j++) {
cout << j;
}
for (int j = 2 * i; j >= i + 1; j--) {
cout << j;
}
cout << "\n";
}
@nitesh16
i loop handles the no of line.
j loop handles each line.