Basic Calculator Challenge

#1

Sir, I have been unable to solve the basic calculator challenge for quite some time. Despite viewing the editorial. Kindly tell me the logic/ solution.

#2

Hello @aan,

You can follow the following approach:

  1. Take the first input as ch
    char ch;
    cin>>ch;

  2. use a while loop which will iterate for each input till the input is not ‘X’ or ‘x’:
    while(ch!=‘X’ || ch!=‘x’){}

  3. Inside the use if else conditional statements:
    3.1. if ch == ‘+’:
    …Take two more inputs n1 and n2 (as integers)
    …and print the addition of both as ouput
    3.2. repeat the same for ‘-’, ‘*’, ‘/’, and ‘%’
    3.3. for any other input you can use else statement:
    …Print ‘Invalid operation. Try again.’ inside that

Share your code, if you would stuck or face any issue.

Hope, this would help.
Give a like, if you are satisfied.

1 Like
#3

How do I fix this?
i know that i should put the ch in a loop but I am unable figure out. Kindly help me out. Thanks…

#include
using namespace std;
int main() {
char ch;
cin>>ch;
while(ch!=‘X’|| ch!=‘x’){
if (ch==’+’){
int n1,n2;
cin>>n1>>n2;
cout<<n1+n2;
}
if (ch==’-’){
int n1,n2;
cin>>n1>>n2;
cout<<n1-n2;
}
if (ch==’’){
int n1,n2;
cin>>n1>>n2;
cout<<n1n2;
}
if (ch==’/’){
int n1,n2;
cin>>n1>>n2;
cout<<n1/n2;
}
if (ch==’%’){
int n1,n2;
cin>>n1>>n2;
cout<<n1%n2;
} else{
cout<<“invalid operation. try again.”;
}
}
return 0;
}

#4

From next time, share your code using Online Coding Blocks IDE.
The way you have send it, is introducing many syntax errors in it.
Steps:

  1. Paste your code on IDE.
  2. Save it there.
  3. Share the URL generated.

Now, coming back to your code:
Solution of what you have asked is,
add the following code as the last statement inside the while loop:
while(){
…
…
…
//last statement:
cin>>ch;
}
The loop would iterate again if ch is neither ‘X’ nor ‘x’.

Hope, this would help.
Give a like, if you are satisfied.

1 Like
#5

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