💡 Balanced Parenthesis

#1


why is it wrong for some testcases

#2

Hey @17manishms
else if(str[i]==’)’|| str[i]==’}’ || str[i]==’]’)
{
if(s.empty())
{
count=1;
}
else{
s.pop();
}
}

The above part of your code is wrong. You need to make separate conditions for ‘}’, ‘]’ and ‘)’. Because ‘)’ will match with only ‘(’, ‘}’ will match with only ‘{’ and ‘[’ will match with only ‘]’. So you need to write the conditions separately. Do try and make this edit.

#3

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