Arvind's odd even

#1

#include
using namespace std;
int main()
{
int n,l,sum;
unsigned long long no;
cin>>n;
for(int i=0;i<n;i++)
{

cin>>no;
sum=0;
while(no!=0)
{  l=no%10;

no/=10;
	sum+=l;}

if(((sum%2==0) and (sum%4==0)) or ((sum%2!=0) and (sum%3==0)))
{
cout<<“Yes”<<endl;

}
else cout<<"No"<<endl;

}

return 0;

}

what is wrong in this code?

#2

@Ashish2001 YOu are performing a wrong operation. It is mentioned that if digit is odd add it to odd sum if digit is even add it to evensum then check oddsum and evensum.

  • Take input of the Number.
  • Declare two variables to store the sum of even numbers and odd numbers.
  • Extract digit one by one ( by % 10).

    1. Check if the number is even or odd.

    2. If even add the number in the variable storing even sum.

  1. Othewise add it in the variable storing odd sum.
  • After the loop, Check if the even sum is divisible by 4.

    1. If True, print Yes.

    2. otherwise print No.

  • Check if the odd sum is divisible by 3.

    1. If True, print Yes.

    2. otherwise print No.

#3

Ok so 0 will be considered even if i fix the code and got 100

#4

No 100 will be considered if you get correct answer. Also If you think I have resolved your doubt please your doubt

#5

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