Arrays-Sum Of Two Arrays

#1

2 test cases are going wrong

#2

Hey,
You are going wrong with the indices,
i recommend you to take a few examples first, work them out on pen paper.

u got to check for conditions when there is 9999+1 or either of the array is size 0 .
please take a look at the code.

in case of further doubts do ask.
Happy coding

#3

i got it to check for array size 0 but why to check array for size 9999+1

#4

vec.push_back((c + sum%10)%10); if© vec.push_back©; reverse(vec.begin(), vec.end()); can you explain these 2 lines of your code

#5

This is a good corner case,
where there will be a carry generated, and you have to add the carry to the answer array.
so it helps to get proper clarity of how to proceed

#6

sum is the addition of value at the two indices and c is the carry
of if sum = 16 and carry from the previous addition is 1
the answer in this column would be 16%10 => (6+1) %10
%10 is done to get just one units place and /10 is done to generate the carry.

vec.push_back© is done for cases where there is a carry generated in the last addition

At the end i have reversed the vector since we are putting the digits in ans vector in left to right fashion
and the answer required is in reverse order.

#8

in the line vec.push_back((c + sum%10)%10); we are adding c to %10 of sum and then again taking its %10 why…suppose sum is 16 and 1 carry is there from last addition so we can write it as vec.push_back((c + sum)%10); this should give the same result as in what u have done we are making 6 from 16 then adding 1 making it 7 and taking %10 of it which is obviously 7 again so think we can remove one “%” from that line

#9

ya definitely. But, there is no problem in keeping that. But thanks for pointing out.