Sir, Why am I getting TLE in 1 Test Case
Solution Link-https://ide.codingblocks.com/s/66016
Hi,
You have incorrectly written the crosscount function.
They way you are counting cross count is wrong way. you doing this is complexity n^2 *(log n)
Please see inversion count again it is done in n*(long n)
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Solution Link- https://ide.codingblocks.com/s/66015
Sir Now i am using array which stores prefix sum then also gettint TLE in 1 test case.
Complexity now must be n*logn . How can i optimise my code further.
You Cross cout fucntion should be like this
int merge(int arr[], int temp[], int left,
int mid, int right)
{
int i, j, k;
int inv_count = 0;
i = left; /* i is index for left subarray*/
j = mid; /* j is index for right subarray*/
k = left; /* k is index for resultant merged subarray*/
while ((i <= mid - 1) && (j <= right))
{
if (arr[i] <= arr[j])
{
temp[k++] = arr[i++];
}
else
{
temp[k++] = arr[j++];
/* this is tricky -- see above
explanation/diagram for merge()*/
inv_count = inv_count + (mid - i);
}
}
/* Copy the remaining elements of left subarray
(if there are any) to temp*/
while (i <= mid - 1)
temp[k++] = arr[i++];
/* Copy the remaining elements of right subarray
(if there are any) to temp*/
while (j <= right)
temp[k++] = arr[j++];
/*Copy back the merged elements to original array*/
for (i = left; i <= right; i++)
arr[i] = temp[i];
return inv_count;
}
Try to this logic of code.
Hit like if you get it!
Thanks for paying attention but I am not getting it
Problem Link-https://hack.codingblocks.com/submission/1893533
Code marked tricky is helpful if we have to find total pairs but actually i have to find sum of smaller numbers so i am using prefix sum ( which is O(1) operation). Your code is for inversion count basic problem, which I suppose is crystal clear to me. In Inversion count, array is sorted in increasing order where in ALPHA SCORE problem i have sorted array in descending order.
I am getting TLE in only 1 test case.