All 3 testcases showing wrong answer

#1

Here is my code :

import java.util.*;
public class Main {

public static int for_char (String A, char a) {
	int maxlen = 1;
	int count = 0;
	int left = 0;
	int right = 0;
	
	while (right < A.length()) {
		if (A.charAt(right) != a) {
			count++;
		}
		
		while (count > 2) {
			if (A.charAt(left) != a) {
				count--;
			}
			left++;
		}
		
		maxlen = Math.max(maxlen, right - left + 1);
		right++;
	}
	return maxlen;
}

public static void main(String args[]) {
	Scanner s = new Scanner(System.in);
	int n = s.nextInt();
	String ss = s.next();
	int max = 1;
	max = Math.max(max, for_char(ss, 'a'));
	max = Math.max(max, for_char(ss, 'b'));
	System.out.println(max);		
}

}

Please tell me where am I going wrong.

#2

@gagan123malik123,
Input:
3
abababab
Correct output:
7
Your Output:
5
When counting say char = ‘a’ :

  1. Maintain a count variable which counts the number of swaps made or the number of 'b’s in our A window.
  2. If you encounter a ‘b’ char at s[ j ] position , increment the count variable. Count should never exceed k .
  3. Take the size of the window at every point using length = j - i + 1;
  4. Compute the max size window this way and do the same for ‘b’ as well.
  5. Compare the maximum size window of ‘a’ and ‘b’
#3

@gagan123malik123,
You are not using the input int n anywhere in your code. It is basically the the maximum number of characters you can change in the string

#4

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