1 count problem

#1

I used 2 pointer approach here but im not able to print the array after splitting 0 with 1’s

#2

Hello @sktg99

What you can do is maintain two variables to keep a track of indices (one for the left end and one for the right end) and update these variables when a new length > maxlength is encountered.

The modified code


The two variables that I have used are “maxLengthL” and “maxLengthR”.

#3

its giving wrong answer for one test case

#4

Hello @sktg99

I have modified my code so that
maxLengthL = -1 and maxLengthR = -1 initially because I thought of a testcase on which my code would fail
Testcase is
5 0
0 0 0 0 0
Here is the modified code
https://ide.codingblocks.com/s/161293 Try this and see if it works.