Related to pytha goras tripelt

[avverma11057]

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[asaurabh_26 (logical coder)]

this is not correct way to ask your doubt
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Related to pythagoras triplet using loop method

formulat you have used is not correct correct formula if(x%2==0){ cout<<((x*x)/4)-1<<" "; cout<<((x*x)/4)+1<<endl; } else{ cout<<(x*x-1)/2<<" "; cout<<(x*x+1)/2<<endl; } correct code Explanation If m>n>0 are integers, then (m2-n2, 2mn, m2-n2) is a Pythagorean triple. This is easily seen with a bit of algebra. Thus, plugging in various (m,n) will give various triples. Now, our goal is to find a triple of the form (m2-n2, 2mn, m2-n2) in which our input value is one of t…

[asaurabh_26 (logical coder)]

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